What is the equilibrium expression for the reaction, P4(s)+5O2(g)P4O10(s)?

Question

What is the equilibrium expression for the reaction, P4(s)+5O2(g)P4O10(s)?  (A)  KC=(1/[O2]5)  (B)  KC=[O2]5  (C)  KC=([P4O10]/5 [P4] [O2])  (D)  KC=([P4O10]/[P4] [O2]5)

Tardigrade Admin · Accepted Answer

P4(s)+5O2(g)P4O10(s) KC=([P4O10(s)]/[P4(s)] [O2(g)]5) We, know that concentration of a solid component is always taken as unity. KC=(1/[O2]5)

Q. What is the equilibrium expression for the reaction, $P_{4} (s) + 5 O_{2} (g) P_{4} O_{10} (s)?$

$K_{C} = \frac{1}{[ O _{2} ] ^{5}}$

$K_{C} = [O_{2}]^{5}$

$K_{C} = \frac{[ P _{4} O _{10} ]}{5 [ P _{4} ] [ O _{2} ]}$

$K_{C} = \frac{[ P _{4} O _{10} ]}{[ P _{4} ] [ O _{2} ] ^{5}}$

$P_{4} (s) + 5 O_{2} (g) P_{4} O_{10} (s)$ $K_{C} = \frac{[ P _{4} O _{10} ( s )]}{[ P _{4} ( s )] [ O _{2} ( g )] ^{5}}$ We, know that concentration of a solid component is always taken as unity. $K_{C} = \frac{1}{[ O _{2} ] ^{5}}$

Q. What is the equilibrium expression for the reaction, P4​(s)+5O2​(g)P4​O10​(s)?

KC​=[O2​]51​

KC​=[O2​]5

KC​=5[P4​][O2​][P4​O10​]​

KC​=[P4​][O2​]5[P4​O10​]​