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Q.
What is the equilibrium expression for the reaction, $ {{P}_{4}}(s)+5{{O}_{2}}(g){{P}_{4}}{{O}_{10}}(s)? $
CMC MedicalCMC Medical 2014
Solution:
$ {{P}_{4}}(s)+5{{O}_{2}}(g){{P}_{4}}{{O}_{10}}(s) $ $ {{K}_{C}}=\frac{[{{P}_{4}}{{O}_{10}}(s)]}{[{{P}_{4}}(s)]\,{{[{{O}_{2}}(g)]}^{5}}} $ We, know that concentration of a solid component is always taken as unity. $ {{K}_{C}}=\frac{1}{{{[{{O}_{2}}]}^{5}}} $