Question

What is the correct mode of hybridisation of the central atom in the following compounds?

	$N{O}_2^{-}$	$S{F}_4$	$P{F}_6^{-}$
a	sp	$s{p}^2$	$s{p}^3$
b	$s{p}^2$	$s{p}^{3}d$	$s{p}^3{d}^2$
c	$s{p}^2$	$s{p}^3$	$d^{2}s{p}^3$
d	$s{p}^3$	$s{p}^3$	$s{p}^3{d}^2$

• A. a
• B. b
• C. c
• D. d

Answer 1

Answer: (B)

Hybridisation of the central atom in compound is given by
$H=\frac{1}{2}[V+M-C+A]$
- For $N{O}_2^{-},H=\frac{1}{2}[5+0-0+1]=3$
$s{p}^2$ hybridisation
- For $S{F}_4,H=\frac{1}{2}[6+4-0+0]=5$
$s{p}^{3}d$ hybridisation
- For $P{F}_6^{-},H=\frac{1}{2}[5+6-0+1]=6$
$s{p}^3{d}^2$ hybridisation.