Question

What is the correct mode of hybridisation of the central atom in the following compounds?

	$NO^-_2$	$SF_4$	$PF^-_6$
a	sp	$sp^2$	$sp^3$
b	$sp^2$	$sp^3d$	$sp^3d^2$
c	$sp^2$	$sp^3$	$d^2sp^3$
d	$sp^3$	$sp^3$	$sp^3d^2$

• A. a
• B. b
• C. c
• D. d

Answer 1

Answer: (B)

Hybridisation of the central atom in compound is given by
$H =\frac{1}{2}[V+M-C+A]$
- For $NO _2^{-}, H=\frac{1}{2}[5+0-0+1]=3$
$s p^2$ hybridisation
- For $SF_4, H=\frac{1}{2}[6+4-0+0]=5$
$s p^3 d$ hybridisation
- For $PF _6^{-}, H=\frac{1}{2}[5+6-0+1]=6$
$s p^3 d^2$ hybridisation.