What is the charge stored on each capacitor C1 and C2 in the circuit shown in figure?

Question

What is the charge stored on each capacitor C1 and C2 in the circuit shown in figure? (A) 6 μ C, 6 μ C (B) 6 μ C , 3 μ C (C) 3 μ C , 6 μ C (D) 3 μ C , 3 μ C

Tardigrade Admin · Accepted Answer

The current in the circuit is I=(12 / 12)=1 A. Potential across d and c is 12 V -3 × 1 V =9 V Capacitance across d and e is C=(1 × 2/1+2)=(2/3) μ F Therefore, charge on either capacitor is (2/3) × 9=6 μ C.

Q. What is the charge stored on each capacitor $C_{1}$ and $C_{2}$ in the circuit shown in figure?

$6 μ C, 6 μ C$

$6 μ C, 3 μ C$

$3 μ C, 6 μ C$

$3 μ C, 3 μ C$

The current in the circuit is $I = (12/12) = 1 A$ .
Potential across $d$ and $c$ is $12 V - 3 \times 1 V = 9 V$
Capacitance across $d$ and $e$ is $C = \frac{1 \times 2}{1 + 2} = \frac{2}{3} μ F$
Therefore, charge on either capacitor is $\frac{2}{3} \times 9 = 6 μ C$ .

Q. What is the charge stored on each capacitor C1​ and C2​ in the circuit shown in figure?

6μC,6μC

6μC,3μC

3μC,6μC

3μC,3μC