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Q.
What is the charge stored on each capacitor $C_{1}$ and $C_{2}$ in the circuit shown in figure?
Current Electricity
Solution:
The current in the circuit is $I=(12 / 12)=1\, A$.
Potential across $d$ and $c$ is $12\, V -3 \times 1\, V =9\, V$
Capacitance across $d$ and $e$ is $C=\frac{1 \times 2}{1+2}=\frac{2}{3} \mu F$
Therefore, charge on either capacitor is $\frac{2}{3} \times 9=6\, \mu C$.