What is the amount of work done when two moles of ideal gas is compressed from a volume of 1 m3 to 10 dm3 at 300 K against a pressure of 100 kPa ?

Question

What is the amount of work done when two moles of ideal gas is compressed from a volume of 1 m3 to 10 dm3 at 300 K against a pressure of 100 kPa ? (A) 99 kJ (B) - 99 kJ (C) 114.9 kJ (D) - 114.9 kJ

Tardigrade Admin · Accepted Answer

Given, number of moles =2 moles V1=1 m3=1000 dm 3 V2=10 dm 3 ∴ We have, work done (W)= -pext d V =-100 kPa ×(10-1000) dm 3 =-100 kPa ×-999 dm 3 =99900 J =99.9 kJ

Q. What is the amount of work done when two moles of ideal gas is compressed from a volume of $1 m^{3}$ to $10 d m^{3}$ at $300 K$ against a pressure of $100 k P a$ ?

$99 k J$

$- 99 k J$

$114.9 k J$

$- 114.9 k J$

Given, number of moles $= 2$ moles

$V_{1} = 1 m^{3} = 1000 d m^{3}$

$V_{2} = 10 d m^{3}$

$∴$ We have, work done $(W) = - p_{e x t} d V$

$= - 100 k P a \times (10 - 1000) d m^{3}$

$= - 100 k P a \times - 999 d m^{3}$

$= 99900 J$

$= 99.9 k J$

Q. What is the amount of work done when two moles of ideal gas is compressed from a volume of 1m3 to 10dm3 at 300K against a pressure of 100kPa ?

99kJ

−99kJ

114.9kJ

−114.9kJ