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Chemistry
What is the amount of work done when two moles of ideal gas is compressed from a volume of 1 m3 to 10 dm3 at 300 K against a pressure of 100 kPa ?
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Q. What is the amount of work done when two moles of ideal gas is compressed from a volume of $1 m^{3}$ to $10 \,dm^{3}$ at $300 \,K $ against a pressure of $100 kPa$ ?
MHT CET
MHT CET 2015
A
$99\, kJ$
B
$- 99 \,kJ$
C
$114.9 \,kJ$
D
$- 114.9 \,kJ$
Solution:
Given, number of moles $=2$ moles
$V_{1}=1 m^{3}=1000 dm ^{3}$
$V_{2}=10 dm ^{3}$
$\therefore $ We have, work done $(W)= -p_{ext} d V$
$=-100 kPa \times(10-1000) dm ^{3}$
$=-100 kPa \times-999 dm ^{3}$
$=99900 J$
$=99.9 kJ$