Question

What is the amount of power delivered by the ac source in the circuit shown (in watts)

• A. 500 watt
• B. 1014 watt
• C. 1514 watt
• D. 2013 watt

Answer 1

Answer: (C)

$i_{1_{\mathrm{ma}}}=\frac{E_{rms}}{\sqrt{X_C^2+R_1^2}}=\frac{130}{13}=10A$
$i_{2_{rma}}=\frac{E_{rms}}{\sqrt{X_L^2+R_2^2}}=13A$
Power dissipated
$=i_{1rms}^2{R}_1+i_{2rms}^2{R}_2=10^2\times 5+13^2\times 6$
$=$ power delivered by battery $=500+169\times 6$
$=1514$ watt