Question

What is the amount of power delivered by the ac source in the circuit shown (in watts)

• A. 500 watt
• B. 1014 watt
• C. 1514 watt
• D. 2013 watt

Answer 1

Answer: (C)

$i_{1_{\operatorname{ma}}}=\frac{E_{ rms }}{\sqrt{X_{C}^{2}+R_{1}^{2}}}=\frac{130}{13}=10 A$
$i_{2_{ rma }}=\frac{E_{ rms }}{\sqrt{X_{L}^{2}+R_{2}^{2}}}=13 A$
Power dissipated
$=i_{1 rms }^{2} R_{1}+i_{2 rms }^{2} R_{2}=10^{2} \times 5+13^{2} \times 6$
$=$ power delivered by battery $=500+169 \times 6$
$=1514$ watt