Question

What is order with respect to $A,B,C$, respectively

[A]	[B]	[C]	rate ( M / sec .)
0.2	0.1	0.0.2	$8.08\times 10^{-3}$
0.1	0.2	0.0.2	$2.01\times 10^{-3}$
0.1	1.8	0.18	$6.03\times 10^{-3}$
0.2	0.1	0.08	$6.464\times 10^{-2}$

• A. $-1,1,3/2$
• B. $-1,1,1/2$
• C. $1,3/2,-1$
• D. $1,-1,3/2$

Answer 1

Answer: (D)

If rate $=k[A{]}^x[B{]}^y[C{]}^z$
From first two given data
$8.08\times 10^{-3}=k[0.2{]}^x[0.1{]}^y[0.02{]}^z$........(i)
$2.01\times 10^{-3}=k[0.1{]}^x[0.2{]}^y[0.02{]}^z$........(ii)
Divide (i) by (ii) we get, $4=2^x(1/2{)}^y$
Similarly, from second and third data
$(9{)}^y(9{)}^z=3$
$2y+2z=1$.
From first and fourth data $4^z=8=2^3$
$2z=3$. So $z=3/2,y=-1,x=1$