1. Tardigrade
  2. Question
  3. Chemistry
  4. What is order with respect to A , B , C, respectively [A] [B] [C] rate ( M / sec .) 0.2 0.1 0.0.2 8.08 × 10-3 0.1 0.2 0.0.2 2.01 × 10-3 0.1 1.8 0.18 6.03 × 10-3 0.2 0.1 0.08 6.464 × 10-2

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Q. What is order with respect to $A , B , C$, respectively
[A] [B] [C] rate ( M / sec .)
0.2 0.1 0.0.2 $8.08 \times 10^{-3}$
0.1 0.2 0.0.2 $2.01 \times 10^{-3}$
0.1 1.8 0.18 $6.03 \times 10^{-3}$
0.2 0.1 0.08 $6.464 \times 10^{-2}$

Chemical Kinetics

Solution:

If rate $= k [ A ]^{x}[ B ]^{y}[ C ]^{z}$
From first two given data
$8.08 \times 10^{-3}=k[0.2]^{x}[0.1]^{y}[0.02]^{z}$........(i)
$2.01 \times 10^{-3}=k[0.1]^{x}[0.2]^{y}[0.02]^{z}$........(ii)
Divide (i) by (ii) we get, $4=2^{x}(1 / 2)^{y}$
Similarly, from second and third data
$ (9) ^y(9)^{z}=3$
$2 y+2 z=1$.
From first and fourth data $4^{z}=8=2^{3}$
$2 z=3$. So $z=3 / 2, y=-1, x=1$