What is Δ n for combustion of 1 mole of benzene, when both the reactants and the products are gas at 298 K

Question

What is Δ n for combustion of 1 mole of benzene, when both the reactants and the products are gas at 298 K  (A) 0 (B) 3/2 (C) -3/2 (D) 1/2

Tardigrade Admin · Accepted Answer

C 6 H 6( g )+(15/2) O 2( g ) longrightarrow 6 CO 2( g ) +3 H 2 O ( g ) Δ n=(6+3)-(1+(15/2))=+1 / 2

Q. What is $Δ n$ for combustion of 1 mole of benzene, when both the reactants and the products are gas at $298 K$