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  4. What is Δ n for combustion of 1 mole of benzene, when both the reactants and the products are gas at 298 K

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Q. What is $ \Delta n $ for combustion of 1 mole of benzene, when both the reactants and the products are gas at $ 298\,K $

Punjab PMETPunjab PMET 2001Equilibrium

Solution:

$C _{6} H _{6}( g )+\frac{15}{2} O _{2}( g ) \longrightarrow 6 CO _{2}( g ) +3 H _{2} O ( g )$
$\Delta n=(6+3)-\left(1+\frac{15}{2}\right)=+1 / 2$