What effect occurs on the frequency of a pendulum if it is taken from the earth surface to deep into a mine?

Question

What effect occurs on the frequency of a pendulum if it is taken from the earth surface to deep into a mine? (A) Increases (B) Decreases (C) First Increases then decreases (D) No effect

Tardigrade Admin · Accepted Answer

f=(1/2 π) √(gd/l) gd=g(1-(d/R)) g decreases, f decreases

Q. What effect occurs on the frequency of a pendulum if it is taken from the earth surface to deep into a mine?

Increases

Decreases

First Increases then decreases

No effect

$f = \frac{1}{2 π} \frac{g _{d}}{l}$
$g_{d} = g (1 - \frac{d}{R})$
$g$ decreases, $f$ decreases

Q. What effect occurs on the frequency of a pendulum if it is taken from the earth surface to deep into a mine?

Increases

Decreases

First Increases then decreases

No effect

f=2π1​lgd​​​ gd​=g(1−Rd​) g decreases, f decreases

$f = \frac{1}{2 π} \frac{g _{d}}{l}$
$g_{d} = g (1 - \frac{d}{R})$
$g$ decreases, $f$ decreases