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  4. What effect occurs on the frequency of a pendulum if it is taken from the earth surface to deep into a mine?

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Q. What effect occurs on the frequency of a pendulum if it is taken from the earth surface to deep into a mine?

Solution:

$f=\frac{1}{2 \pi} \sqrt{\frac{g_{d}}{l}}$
$g_{d}=g\left(1-\frac{d}{R}\right)$
$g$ decreases, $f $ decreases