What are X and Y respectively in the following reaction? Z -product [X] E -product

Question

What are X and Y respectively in the following reaction? Z -product <-[Y] 2 -butyne ->[X] E -product (A) Na / NH 3 (liq.) and Pd / BaSO 4+ H 2 (B) Ni / 140° C and Pd / BaSO 4+ H 2 (C) Ni / 140° C and Na / NH 3 (liq.) (D) Pd / BaSO 4+ H 2 and Na / NH 3 (liq.)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/a590e44d3c0738f8012b58164c54b418-.png" /> Hence, reagent X and Y are respectively Na, NH 3 and Pd / BaSO 4+ H 2

Q. What are $X$ and $Y$ respectively in the following reaction?
$Z$ -product $Y 2$ -butyne $X E$ -product

$N a / N H_{3}$ (liq.) and $P d / B a S O_{4} + H_{2}$

$N i /14 0^{\circ} C$ and $P d / B a S O_{4} + H_{2}$

$N i /14 0^{\circ} C$ and $N a / N H_{3}$ (liq.)

$P d / B a S O_{4} + H_{2}$ and $N a / N H_{3}$ (liq.)

Hence, reagent $X$ and $Y$ are respectively $N a$ , $N H_{3}$ and $P d / B a S O_{4} + H_{2}$

Q. What are X and Y respectively in the following reaction? Z -product Y​2 -butyne X​E -product

Na/NH3​ (liq.) and Pd/BaSO4​+H2​

Ni/140∘C and Pd/BaSO4​+H2​

Ni/140∘C and Na/NH3​ (liq.)

Pd/BaSO4​+H2​ and Na/NH3​ (liq.)