Question

What are $X$ and $Y$ respectively in the following reaction?
$Z$ -product $\ce{<-[{Y}]} 2$ -butyne $\ce{->[{X}]} E$ -product

• A. $Na / NH _{3}$ (liq.) and $Pd / BaSO _{4}+ H _{2}$
• B. $Ni / 140^{\circ} C$ and $Pd / BaSO _{4}+ H _{2}$
• C. $Ni / 140^{\circ} C$ and $Na / NH _{3}$ (liq.)
• D. $Pd / BaSO _{4}+ H _{2}$ and $Na / NH _{3}$ (liq.)

Answer 1

Answer: (A)

Hence, reagent $X$ and $Y$ are respectively $Na$, $NH _{3}$ and $Pd / BaSO _{4}+ H _{2}$