Question

What are $X$ and $Y$ in the following reaction sequence?
$C_2{H}_{5}OH\stackrel{C{l}_2}{\to }(X)\stackrel{C{l}_2}{\to }Y$.

• A. $C_2{H}_{5}Cl,C{H}_{3}CHO$
• B. $C{H}_{3}CHO,C{H}_{3}C{O}_{2}H$
• C. $C{H}_{3}CHO,CC{l}_{3}CHO$
• D. $C_2{H}_{5}Cl,CC{l}_{3}CHO$

Answer 1

Answer: (C)

At first on reaction with alcohol, $C{l}_2$ with act as oxidising agent and convert $C_2{H}_{5}OH$ into $C{H}_3-CHO(X)$ In the second step chlorination will take place and $3-Hs$ will be replaced by $3Cl$ and $Y$ will be $C{l}_3\cdot C-CHO$
$C_2{H}_{5}OH+C{l}_2\to C{H}_3-CHO(x)$. [Oxidation]
$C{H}_3-CHO+C{l}_2\to C{l}_{3}C-CHO$ [Chlorination]