Question

Weight-of $4L$ of $N_2$ gas at NTP is:

• A. 56 g
• B. 2.5 g
• C. 5 g
• D. 28 g

Answer 1

Answer: (C)

$\because$ Weight of $22.4L$ of nitrogen at NTP $=28g$
$\therefore$ Weight of $4L$ of $N_3$ gas at
$NTP=\frac{28}{22.4}\times 4=5g$