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  4. Weight-of 4 L of N2 gas at NTP is:

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Q. Weight-of $4\, L$ of $N_{2}$ gas at NTP is:

J & K CETJ & K CET 2002

Solution:

$\because$ Weight of $22.4\, L$ of nitrogen at NTP $=28\, g$
$\therefore $ Weight of $4\, L$ of $N_3$ gas at
$NTP=\frac{28}{22.4} \times 4=5\, g$