Weight of 112 ml of oxygen at NTP on liquefaction would be

Question

Weight of 112 ml of oxygen at NTP on liquefaction would be (A) 0.32 g (B) 0.64 g (C) 0.16 g (D) 0.96 g

Tardigrade Admin · Accepted Answer

22400 ml is the volume of O2 at NTP=32 gm of O2 1 ml is the volume of O2 at NTP=(32/22400) 112 ml is the volume of O2 at NTP=(32/22400)× 112 =0.16 g of O2

Q. Weight of $112 m l$ of oxygen at $NTP$ on liquefaction would be

$0.32 g$

$0.64 g$

$0.16 g$

$0.96 g$

$22400 m l$ is the volume of $O_{2}$ at $NTP = 32 g m$ of $O_{2}$
1 ml is the volume of $O_{2}$ at $NTP = \frac{32}{22400}$
112 ml is the volume of $O_{2}$ at $NTP = \frac{32}{22400} \times 112$
$= 0.16 g$ of $O_{2}$

Q. Weight of 112ml of oxygen at NTP on liquefaction would be

0.32g

0.64g

0.16g

0.96g