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  4. Weight of 112 ml of oxygen at NTP on liquefaction would be

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Q. Weight of $112\, ml$ of oxygen at $NTP$ on liquefaction would be

States of Matter

Solution:

$22400\, ml$ is the volume of $O_{2}$ at $NTP=32\,gm$ of $O_{2}$
1 ml is the volume of $O_{2}$ at $NTP=\frac{32}{22400}$
112 ml is the volume of $O_{2}$ at $NTP=\frac{32}{22400}\times 112$
$=0.16\,g$ of $O_{2}$