We can say that the energy of the photon of frequency v is given by E=h v, where h is Planck's constant. The momentum of a photon is p=h / λ, where λ is the wavelength of photon. Then we may conclude that velocity of light is equal to

Question

We can say that the energy of the photon of frequency v is given by E=h v, where h is Planck's constant. The momentum of a photon is p=h / λ, where λ is the wavelength of photon. Then we may conclude that velocity of light is equal to (A) (E / p)1 / 2 (B) E / p (C) E p (D) (E / p)2

Tardigrade Admin · Accepted Answer

p=m v=(h/λ) and E=(h c/λ) ∴ E=(c/λ) ⋅ p ⋅ λ=c. p. ⇒ c=(E/p)

Q. We can say that the energy of the photon of frequency $v$ is given by $E = h v,$ where $h$ is Planck's constant. The momentum of a photon is $p = h / λ,$ where $λ$ is the wavelength of photon. Then we may conclude that velocity of light is equal to

$(E / p)^{1/2}$

$E / p$

$Ep$

$(E / p)^{2}$

$p = m v = \frac{h}{λ}$ and $E = \frac{h c}{λ}$

$∴ E = \frac{c}{λ} \cdot p \cdot λ = c . p .$

$\Rightarrow c = \frac{E}{p}$

Q. We can say that the energy of the photon of frequency v is given by E=hv, where h is Planck's constant. The momentum of a photon is p=h/λ, where λ is the wavelength of photon. Then we may conclude that velocity of light is equal to

(E/p)1/2

E/p

Ep

(E/p)2