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Q. We can say that the energy of the photon of frequency $v$ is given by $E=h v,$ where $h$ is Planck's constant. The momentum of a photon is $p=h / \lambda,$ where $\lambda$ is the wavelength of photon. Then we may conclude that velocity of light is equal to

Structure of Atom

Solution:

$p=m v=\frac{h}{\lambda}$ and $E=\frac{h c}{\lambda}$

$\therefore E=\frac{c}{\lambda} \cdot p \cdot \lambda=c. p.$

$\Rightarrow c=\frac{E}{p}$