VSEPR theory suggests that bond length and bond angle depend upon the presence or absence of lone pairs. If the bond angle of H-O-H in H2O is 105° (.approx..) , then the bond angle of F-O-F in F2O will be

Question

VSEPR theory suggests that bond length and bond angle depend upon the presence or absence of lone pairs. If the bond angle of H-O-H in H2O is 105° (.approx..) , then the bond angle of F-O-F in F2O will be (A) greater than 105°  (B) lesser than 105°  (C) equal to 105°  (D) equal to 180°

Tardigrade Admin · Accepted Answer

In F2O, F is more electronegative which attracts the bond pair electrons away from central oxygen atom. Which decreases the repulsion between bond pair of electrons, hence bond angle decreases.

Q. $V SEPR$ theory suggests that bond length and bond angle depend upon the presence or absence of lone pairs. If the bond angle of $H - O - H$ in $H_{2} O$ is $10 5^{\circ} (a pp ro x .)$ , then the bond angle of $F - O - F$ in $F_{2} O$ will be

greater than $10 5^{\circ}$

lesser than $10 5^{\circ}$

equal to $10 5^{\circ}$

equal to $18 0^{\circ}$

In $F_{2} O, F$ is more electronegative which attracts the bond pair electrons away from central oxygen atom. Which decreases the repulsion between bond pair of electrons, hence bond angle decreases.

Q. VSEPR theory suggests that bond length and bond angle depend upon the presence or absence of lone pairs. If the bond angle of H−O−H in H2​O is 105∘(approx.) , then the bond angle of F−O−F in F2​O will be

greater than 105∘

lesser than 105∘

equal to 105∘

equal to 180∘