1. Tardigrade
  2. Question
  3. Chemistry
  4. VSEPR theory suggests that bond length and bond angle depend upon the presence or absence of lone pairs. If the bond angle of H-O-H in H2O is 105° (.approx..) , then the bond angle of F-O-F in F2O will be

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Q. $VSEPR$ theory suggests that bond length and bond angle depend upon the presence or absence of lone pairs. If the bond angle of $H-O-H$ in $H_{2}O$ is $105^\circ \left(\right.approx.\left.\right)$ , then the bond angle of $F-O-F$ in $F_{2}O$ will be

NTA AbhyasNTA Abhyas 2020Chemical Bonding and Molecular Structure

Solution:

In $F_{2}O, \, F$ is more electronegative which attracts the bond pair electrons away from central oxygen atom. Which decreases the repulsion between bond pair of electrons, hence bond angle decreases.