Question

Volume-temperature graph at atmospheric pressure for a monoatomic gas ( $Vin{m}^3,Tincelcius$ ) is

• A.
• B.
• C.
• D.

Answer 1

Answer: (A)

$$\begin{gathered} PV=nRt \\ V=\frac{nR}{P}(T_c+273.15) \\ V=(\frac{nR}{P})T_c+\frac{273.15nR}{P} \end{gathered}$$
Positive slope positive intercept
The volume of gas is zero at absolute zero temperature ( $0\text{K}$ )
Thus, the volume has a positive value at $0^{\circ }\text{C}$ since the volume is directly proportonal to the absolute temperature and $0\text{K}=-273.15^{\circ }\text{C}$