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Q.
Volume-temperature graph at atmospheric pressure for a monoatomic gas ( $V \, in \, m^{3}, \, T \, in \, celcius$ ) is
NTA AbhyasNTA Abhyas 2022
Solution:
$PV=nRt \\ V=\frac{n R}{P}\left(\right.T_{c}+273.15\left.\right) \\ V=\left(\right. \frac{n R}{P} \left.\right)T_{c}+\frac{273.15 n R}{P}$
Positive slope positive intercept
The volume of gas is zero at absolute zero temperature ( $0 \, \text{K}$ )
Thus, the volume has a positive value at $0 ^\circ \text{C}$ since the volume is directly proportonal to the absolute temperature and $0 \, \, \text{K} = - 273.15 ^\circ \text{C}$