Volume of CO 2 obtained by the complete decomposition of 9.85 g BaCO 3 is

Question

Volume of CO 2 obtained by the complete decomposition of 9.85 g BaCO 3 is (A) 2.24 L (B) 1.12 L (C) 0.84 L (D) 0.56 L

Tardigrade Admin · Accepted Answer

BaCO 3 xrightarrow Δ BaO + CO 2 Molecular weight of BaCO 3 =137+12+16 × 3=197 u. ∵ 197 g BaCO 3 gives 222.4 L CO 2 at NTP ∴ 9.85 g BaCO 3 gives (22.4/197) × 9.85 L CO 2 at NTP Volume of CO 2=1.12 L

Q. Volume of $C O_{2}$ obtained by the complete decomposition of $9.85 g B a C O_{3}$ is

2.24 L

1.12 L

0.84 L

0.56 L

$B a C O_{3} Δ B a O + C O_{2}$
Molecular weight of $B a C O_{3}$
$= 137 + 12 + 16 \times 3 = 197 u$ .
$∵ 197 g B a C O_{3}$ gives $222.4 L C O_{2}$ at NTP
$∴ 9.85 g B a C O_{3}$ gives $\frac{22.4}{197} \times 9.85 L$
$C O_{2}$ at NTP Volume of $C O_{2} = 1.12 L$

Q. Volume of CO2​ obtained by the complete decomposition of 9.85gBaCO3​ is