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  4. Volume of CO 2 obtained by the complete decomposition of 9.85 g BaCO 3 is

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Q. Volume of $CO _{2}$ obtained by the complete decomposition of $9.85\, g\, BaCO _{3}$ is

Chhattisgarh PMTChhattisgarh PMT 2007

Solution:

$BaCO _{3} \xrightarrow {\Delta} BaO + CO _{2}$
Molecular weight of $BaCO _{3}$
$=137+12+16 \times 3=197\, u$.
$\because 197 \,g\, BaCO _{3}$ gives $222.4 \,L\, CO _{2}$ at NTP
$\therefore 9.85\, g\, BaCO _{3}$ gives $\frac{22.4}{197} \times 9.85 L$
$CO _{2}$ at NTP Volume of $CO _{2}=1.12 \,L$