Question

Volume occupied by one molecule of water $($ density $=1gc{m}^{-3})$ is :

• A. $9.0\times 10^{-23}c{m}^3$
• B. $6.023\times 10^{-23}c{m}^3$
• C. $3.0\times 10^{-23}c{m}^3$
• D. $5.5\times 10^{-23}c{m}^3$

Answer 1

Answer: (C)

$\therefore$ Volume occupied by $1$ gram water $=1c{m}^3$
or Volume occupied by
$\frac{6.023\times 10^{23}}{18}$ molecules of water $=1c{m}^3$
$[\therefore 1g$ water $=\frac{1}{18}$ moles of water $]$
Thus volume occupied by 1 molecule of water
$=\frac{1\times 18}{6.023\times 10^{23}}c{m}^3=3.0\times 10^{-23}c{m}^3$