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Q.
Volume occupied by one molecule of water $\left(\right.$ density $\left.=1 \,g\, cm ^{-3}\right)$ is :
Some Basic Concepts of Chemistry
Solution:
$\therefore$ Volume occupied by $1$ gram water $=1\, cm ^{3}$
or Volume occupied by
$\frac{6.023 \times 10^{23}}{18}$ molecules of water $=1\,cm ^{3}$
$\left[\therefore\, 1 g\right.$ water $=\frac{1}{18}$ moles of water $]$
Thus volume occupied by 1 molecule of water
$=\frac{1 \times 18}{6.023 \times 10^{23}} cm ^{3}=3.0 \times 10^{-23}\, cm ^{3}$