Voltmeters V1 and V2 are connected in series across a D.C. line. V1 reads 80 volts and has a per volt resistance of 200 ohms. V2 has a total resistance of 32 kilo-ohms. The line voltage is

Question

Voltmeters V1 and V2 are connected in series across a D.C. line. V1 reads 80 volts and has a per volt resistance of 200 ohms. V2 has a total resistance of 32 kilo-ohms. The line voltage is (A) 120 volts (B) 160 volts (C) 220 volts (D) 240 volts

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<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/8e4289a40417ddee5942598051e1f762-.png" /> R1=80 × 200=16000 Ω=16 k Ω Current flowing through V1= Current flowing through V2=(80/16 × 103)=5 × 10-3 A So, potential difference across V2 is V2=5 × 10-3 × 32 × 103=160 text volt Hence, line voltage, V=V1+V2 =80+160=240 V

Q. Voltmeters V1​ and V2​ are connected in series across a D.C. line. V1​ reads 80 volts and has a per volt resistance of 200 ohms. V2​ has a total resistance of 32 kilo-ohms. The line voltage is

120 volts

160 volts

220 volts

240 volts

R1​=80×200=16000Ω=16kΩ Current flowing through V1​= Current flowing through V2​=16×10380​=5×10−3A So, potential difference across V2​ is V2​=5×10−3×32×103=160 volt Hence, line voltage, V=V1​+V2​ =80+160=240V

Q. Voltmeters $V_{1}$ and $V_{2}$ are connected in series across a D.C. line. $V_{1}$ reads $80$ volts and has a per volt resistance of $200$ ohms. $V_{2}$ has a total resistance of $32$ kilo-ohms. The line voltage is