Question

Velocity of a particle is given as $\upsilon =(180-16t)m{s}^{-1}$ . Then its acceleration will be

• A. zero
• B. $8m/s^2$
• C. $-16m/s^2$
• D. $4m/s^2$

Answer 1

Answer: (C)

$a=\frac{d\upsilon }{dt}=\frac{d}{dt}(180-16t)=-16m{s}^{-2}$