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  4. Velocity of a particle is given as upsilon= (180 - 16t) m s-1 . Then its acceleration will be

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Q. Velocity of a particle is given as $\upsilon= (180 - 16t) m\,s^{-1}$ . Then its acceleration will be

Motion in a Straight Line

Solution:

$a = \frac{d \, \upsilon}{dt} = \frac{d}{dt} (180 - 16t) = - 16 \, m \, s^{-2}$