Question

Vapour density of a metal chloride is $66$. Its oxide contains $53\%$ metal. The atomic weight of the metal is

• A. $21$
• B. $54$
• C. $27.06$
• D. $2.086$

Answer 1

Answer: (C)

Let wt. of metal oxide $=100g$
wt. of metal $=53g$
wt. of oxygen $=47g$
Equivalent weight of oxygen
$=\frac{\text{wt.of metal}}{\text{wt.of oxygen}}\times 8=\frac{53}{47}\times 8=9.02$
Valency$=\frac{2\times V.D}{E+35.5}=\frac{2\times 66}{9+35.5}=\frac{132}{44.5}=2.96\approx 3$
$\therefore$ Atomic weight = Equivalent weight $\times$ Valency
$=9.20\times 3=27.06$