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Q. Vapour density of a metal chloride is $66$. Its oxide contains $53\%$ metal. The atomic weight of the metal is

Some Basic Concepts of Chemistry

Solution:

Let wt. of metal oxide $= 100 g$
wt. of metal $= 53 g$
wt. of oxygen $= 47 g$
Equivalent weight of oxygen
$=\frac{\text{wt.of metal}}{\text{wt.of oxygen}}\times8=\frac{53}{47}\times8=9.02$
Valency$=\frac{2\times V.D}{E+35.5}=\frac{2\times66}{9+35.5}=\frac{132}{44.5}=2.96\approx3$
$\therefore $ Atomic weight = Equivalent weight $\times$ Valency
$= 9.20 \times 3 = 27.06$