Question

$V$ versus $T$ curves at constant pressure $P_1$ and $P_2$ for an ideal gas are shown in figure. Here,

• A. $P_1>P_2$
• B. $P_1<P_2$
• C. $P_1=P_2$
• D. $P_1\ge P_2$

Answer 1

Answer: (A)

$PV=\mu RTorP=\frac{\mu RT}{V}orP=\frac{\mu R}{\frac{V}{T}}$
$orP=\frac{\mu R}{tan\theta }$ , where $tan\theta$ is the slope of the graph.
So, more the slope, lesser will be the pressure.