Question

$V$ versus $T$ curves at constant pressure $P_{1}$ and $ \, P_{2}$ for an ideal gas are shown in figure. Here,

• A. $P_{1}>P_{2}$
• B. $P_{1} < P_{2}$
• C. $P_{1}=P_{2}$
• D. $P_{1}\geq P_{2}$

Answer 1

Answer: (A)

$PV=\mu RT \, or \, P=\frac{\mu R T}{V} \, or \, P=\frac{\mu R}{\frac{V}{T}}$
$or \, P=\frac{\mu R}{tan \theta }$ , where $tan \theta $ is the slope of the graph.
So, more the slope, lesser will be the pressure.