Question

Using valence bond theory, the complex $[Cr(H_{2}O{)}_6{]}^{3+}$ can be described as

• A. $s{p}^3{d}^2$, outer orbital complex, paramagnetic
• B. $ds{p}^2$, inner orbital complex, diamagnetic
• C. $d^{2}s{p}^3$ , inner orbital complex, paramagnetic
• D. $d^{2}s{p}^3$, outer orbital complex, diamagnetic

Answer 1

Answer: (C)

In $[Cr(H_{2}O{)}_6{]}^{3+}$ , oxidation state of $Cr=+3,C{r}^{3+}=3d^3$
$[Cr(H_{2}O{)}_6{]}^{3+}$ :
It is an inner orbital complex. Due to presence of three unpaired electrons, it is paramagnetic