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Q.
Using valence bond theory, the complex $[Cr(H_{2}O )_{6}]^{3+}$ can be described as
Coordination Compounds
Solution:
In $[Cr(H_{2}O )_{6}]^{3+}$ , oxidation state of $Cr = +3, Cr^{3+} = 3d^{3}$
$[Cr(H_{2}O)_{6}]^{3+}$ :
It is an inner orbital complex. Due to presence of three unpaired electrons, it is paramagnetic