A. The number of 4 different digits =7P4 =(7−4)!7! =7×6×5×4=840
B. The numbers exactly divisible by 2
= Number of ways of filling first 3 places × Number of ways of filling units's place =6P3×3 =(6−3)!6!×3=(3!)6!×3 =6×5×4×3=360
C. Number of 4-digit numbers divisible by 25= Numbers ending with 25 or 75 =□□5×4□□25or75 =5×4×2=40 (∵ when numbers end with 25 or 75 , the other two places can be filled in 5 and 4 ways)
D. Number of 4-digit numbers divisible by 4= Numbers ending with 12,16,24,32,36,64,72,76,52,56
Now, number ending with 12=4×□5×□1×□1□=20
Similarly, numbers ending with other number (16,24,…)=20 each ∴ Required numbers =10×20=200