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Q. Using the digits 1,2,3,4,5,6,7, a number of 4 different digits is formed. Find
Column I Column II
A How many numbers are formed? 1 840
B How many numbers are exactly divisible by 2 ? 2 200
C How many numbers are exactly divisible by 25 ? 3 360
D How many of these are exactly divisible by 4 ? 4 40

Match the questions in Column I with Column II and choose the correct option from the codes given below.

Permutations and Combinations

Solution:

A. The number of 4 different digits =7P4
=7!(74)!
=7×6×5×4=840
B. The numbers exactly divisible by 2
= Number of ways of filling first 3 places × Number of ways of filling units's place
=6P3×3
=6!(63)!×3=6!(3!)×3
=6×5×4×3=360
C. Number of 4-digit numbers divisible by 25= Numbers ending with 25 or 75
=5×425or75
=5×4×2=40
( when numbers end with 25 or 75 , the other two places can be filled in 5 and 4 ways)
D. Number of 4-digit numbers divisible by 4= Numbers ending with 12,16,24,32,36,64,72,76,52,56
Now, number ending with 12=4×5×1×1=20
Similarly, numbers ending with other number (16,24,)=20 each
Required numbers =10×20=200