Using the data provided, calculate the multiple bond energy ( kJ mol -1) of a C = C bond in C 2 H 2. That energy is (take the bond energy of C - H bond as 350 kJ mol -1 ). 2 C ( s )+ H 2( g ) arrow C 2 H 2 Δ H =225 kJ mol -1 2 C ( s ) arrow C ( g ) Δ H =1410 kJ mol -1 H2(g) arrow 2 H (g) Δ H =330 kJ mol -1

Question

Using the data provided, calculate the multiple bond energy ( kJ mol -1) of a C = C bond in C 2 H 2. That energy is (take the bond energy of C - H bond as 350 kJ mol -1 ). 2 C ( s )+ H 2( g ) arrow C 2 H 2 Δ H =225 kJ mol -1 2 C ( s ) arrow C ( g ) Δ H =1410 kJ mol -1 H2(g) arrow 2 H (g) Δ H =330 kJ mol -1 (A) 1165 kJ mol -1 (B) 837 kJ mol -1 (C) 865 kJ mol -1 (D) 815 kJ mol -1

Tardigrade Admin · Accepted Answer

We know that
Binding energy = Total energy of reactants - Total energy of products
So, we have

225 = 2 (C - C) + 1 (H - H) - 2 (C - H) + 1 (C \equiv C)

225 = 1410 + 330 - 2 \times 350 + (C \equiv C)

Solving, we get the value of

C \equiv C

as

815 k J m o l^{- 1}

$1165 k J m o l^{- 1}$

$837 k J m o l^{- 1}$

$865 k J m o l^{- 1}$

$815 k J m o l^{- 1}$

We know that
Binding energy = Total energy of reactants - Total energy of products
So, we have
$225 = 2 (C - C) + 1 (H - H) - 2 (C - H) + 1 (C \equiv C)$
$225 = 1410 + 330 - 2 \times 350 + (C \equiv C)$
Solving, we get the value of $C \equiv C$ as $815 k J m o l^{- 1}$

Q. Using the data provided, calculate the multiple bond energy (kJmol−1) of a C=C bond in C2​H2​. That energy is (take the bond energy of C−H bond as 350kJmol−1 ). 2C(s)+H2​(g)→C2​H2​ΔH=225kJmol−1 2C(s)→C(g)ΔH=1410kJmol−1 H2​(g)→2H(g)ΔH=330kJmol−1

1165kJmol−1

837kJmol−1

865kJmol−1

815kJmol−1

We know that Binding energy = Total energy of reactants - Total energy of products So, we have 225=2(C−C)+1(H−H)−2(C−H)+1(C≡C) 225=1410+330−2×350+(C≡C) Solving, we get the value of C≡C as 815kJmol−1

$1165 k J m o l^{- 1}$

$837 k J m o l^{- 1}$

$865 k J m o l^{- 1}$

$815 k J m o l^{- 1}$

We know that
Binding energy = Total energy of reactants - Total energy of products
So, we have
$225 = 2 (C - C) + 1 (H - H) - 2 (C - H) + 1 (C \equiv C)$
$225 = 1410 + 330 - 2 \times 350 + (C \equiv C)$
Solving, we get the value of $C \equiv C$ as $815 k J m o l^{- 1}$