1. Tardigrade
  2. Question
  3. Chemistry
  4. Using the data provided, calculate the multiple bond energy ( kJ mol -1) of a C = C bond in C 2 H 2. That energy is (take the bond energy of C - H bond as 350 kJ mol -1 ). 2 C ( s )+ H 2( g ) arrow C 2 H 2 Δ H =225 kJ mol -1 2 C ( s ) arrow C ( g ) Δ H =1410 kJ mol -1 H2(g) arrow 2 H (g) Δ H =330 kJ mol -1

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Q. Using the data provided, calculate the multiple bond energy $\left( kJ \,mol ^{-1}\right)$ of a $C = C$ bond in $C _{2} H _{2}$. That energy is (take the bond energy of $C - H$ bond as $350\, kJ\, mol ^{-1}$ ).
$2 C ( s )+ H _{2}( g ) \rightarrow C _{2} H _{2} \Delta H =225 \,kJ\, mol ^{-1}$
$2 C ( s ) \rightarrow C ( g ) \Delta H =1410 \,kJ \,mol ^{-1}$
$H_{2}(g) \rightarrow 2 H (g) \Delta H =330 \,kJ \,mol ^{-1}$

JEE AdvancedJEE Advanced 2012

Solution:

We know that
Binding energy = Total energy of reactants - Total energy of products
So, we have
$225=2( C - C )+1( H - H )-2( C - H )+1( C \equiv C )$
$225=1410+330-2 \times 350+( C \equiv C )$
Solving, we get the value of $C \equiv C$ as $815 \,kJ\, mol ^{-1}$