Using screw gauge of pitch 0.1 cm and 50 divisions on its circular scale, the thickness of an object is measured. It should correctly be recorded as

Question

Using screw gauge of pitch 0.1 cm and 50 divisions on its circular scale, the thickness of an object is measured. It should correctly be recorded as (A) 2.123 cm (B) 2.125 cm (C) 2.121 cm (D) 2.124 cm

Tardigrade Admin · Accepted Answer

L C=( text pitch /C S D)=(0.1 cm /50)=0.002 cm So any measurement will be integral Multiple of LC So ans. will be 2.124 cm

Q. Using screw gauge of pitch $0.1 c m$ and $50$ divisions on its circular scale, the thickness of an object is measured. It should correctly be recorded as

$2.123 c m$

$2.125 c m$

$2.121 c m$

$2.124 c m$

$L C = \frac{pitch}{CS D} = \frac{0.1 c m}{50} = 0.002 c m$
So any measurement will be integral Multiple of $L C$ So ans. will be $2.124 c m$

Q. Using screw gauge of pitch 0.1cm and 50 divisions on its circular scale, the thickness of an object is measured. It should correctly be recorded as

2.123cm

2.125cm

2.121cm

2.124cm