1. Tardigrade
  2. Question
  3. Physics
  4. Using screw gauge of pitch 0.1 cm and 50 divisions on its circular scale, the thickness of an object is measured. It should correctly be recorded as

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. Using screw gauge of pitch $0.1 cm$ and $50$ divisions on its circular scale, the thickness of an object is measured. It should correctly be recorded as

JEE MainJEE Main 2020Physical World, Units and Measurements

Solution:

$L C=\frac{\text { pitch }}{C S D}=\frac{0.1 cm }{50}=0.002 cm$
So any measurement will be integral Multiple of $LC$ So ans. will be $2.124 cm$