Using equipartition of energy, the specific heat (in J kg-1 K-1 of aluminium at room temperature can be estimated to be (atomic weight of aluminium = 27)

Question

Using equipartition of energy, the specific heat (in J kg-1 K-1 of aluminium at room temperature can be estimated to be (atomic weight of aluminium = 27) (A) 25 (B) 410 (C) 925 (D) 1850

Tardigrade Admin · Accepted Answer

Dulong and Petit found that the heat capacity of a mole of many solid substances is about

3 R

, that is about

25 J / K 1

mole of

A C

is equivalent to

27 g

Therefore, specific heat in

\frac{J}{k g K}

is given by

s = \frac{25}{27 \times 1 0 ^{- 3}} = \frac{25000}{27} = 925 \frac{J}{k g K}

Q. Using equipartition of energy, the specific heat (in Jkg−1K−1 of aluminium at room temperature can be estimated to be (atomic weight of aluminium =27)

25

410

925

1850

Dulong and Petit found that the heat capacity of a mole of many solid substances is about 3R, that is about 25J/K1 mole of AC is equivalent to 27g Therefore, specific heat in kgKJ​ is given by s=27×10−325​=2725000​=925kgKJ​

Q. Using equipartition of energy, the specific heat (in $J k g^{- 1} K^{- 1}$ of aluminium at room temperature can be estimated to be (atomic weight of aluminium $= 27$ )

Dulong and Petit found that the heat capacity of a mole of many solid substances is about $3 R$ , that is about $25 J / K 1$ mole of $A C$ is equivalent to $27 g$
Therefore, specific heat in $\frac{J}{k g K}$ is given by
$s = \frac{25}{27 \times 1 0 ^{- 3}} = \frac{25000}{27} = 925 \frac{J}{k g K}$