Urine normally has a pH of 6 . If a patient eliminates 1.3 litre of urine per day. How many moles of H +ions does he urinate ?

Question

Urine normally has a pH of 6 . If a patient eliminates 1.3 litre of urine per day. How many moles of H +ions does he urinate ? (A) 1.3 × 10-3 (B) 1.3 × 10-4 (C) 1.3 × 10-7 (D) 1.3 × 10-6

Tardigrade Admin · Accepted Answer

pH =6 [ H +]=10-6 M Mol = M × V =10-6 × 1.3=1.3 × 10-6 mol

Q. Urine normally has a $p H$ of $6$ . If a patient eliminates $1.3$ litre of urine per day. How many moles of $H^{+}$ ions does he urinate ?

$1.3 \times 1 0^{- 3}$

$1.3 \times 1 0^{- 4}$

$1.3 \times 1 0^{- 7}$

$1.3 \times 1 0^{- 6}$

$p H = 6$
$[H^{+}] = 1 0^{- 6} M$
Mol $= M \times V$
$= 1 0^{- 6} \times 1.3 = 1.3 \times 1 0^{- 6} m o l$

Q. Urine normally has a pH of 6 . If a patient eliminates 1.3 litre of urine per day. How many moles of H+ions does he urinate ?

1.3×10−3

1.3×10−4

1.3×10−7

1.3×10−6